【问题说明】通过实际案例描述，根据配送点和业务需求量，进行最优路径计算。 从物流中心点出发，配送多个客户点后返回出发点，根据车辆数量、装载限制、车辆服务成本、运行距离限制等条件选择最佳运输路径(总里程最短)，使成本最小化，配送订单最大化，满载率达到从一个配送中心向各个销售点配送货物，通过算法决定配送中心的每辆车的配送方案，进行下一次配送，包括配送给哪个顾客、配送量【测试数据和说明】某物流中心有5辆配送车辆，车辆的最大载重量为全部物流中心和20个客户的坐标及其客户的需求量是随机发生的。 其中物流中心坐标为(14.2KM，13.1km ) )，合理安排车辆配送路线和载重量，确保配送总里程3358 www.Sina.com/http://www.Sina.com/http://3358 www.Sina.com/12.888 18.43.40.43358 www.Sina.com/15.416.61.2http://www.Sina.com/18.915.21.5551 10.67.61.7http://www.Sina.com/8.68.40.6http://www.Sina.com/12.52 13.85.20.4http://www.Sina.com/6 1.88 17.1111.9http://www.Sina.com/7.411.7http://www.Sina.com/0.22.81.1http://www.Sina.com/11.919 . 6.45.61.7http://www.Sina.com/9.614.81.5说明：各客户相互之间及物流中心与客户之间的距离均采用直线距离
1 .传统贪婪算法# include iostream # include algorithm # include stdlib.h # includecmathusingnamespacestd； 双精度映射[ 21 ] [3]={ 14.2、13.1、0、12.8、8.5、0.1、18.4、3.4、15.4、16.6、1.2、18.9、15.2、1.5、15.5 1.2 bool flag[21]={false}； 双面磁盘(双面1，双面y1，双面x2，双面y2 ) )返回(双面) pow ) (pow ) ) x2-x1 )，2 (pow ) ) YY i 21； I ) for(intj=I1； j 21； j ) { distances [ I ] [ j ]=dist (map [ I ] [0]，map[i][1]，map[j][0]，map[j][1]； 距离[ j ] [ I ]=距离[ I ] [ j ]； }距离[ I ] [ I ]=10000； }//indexofmineveryrowintseletmin (双距离(21 )、int row、双和) ) {双最小=10000； int minIndex=22； for(intI=0； i 21； I ) if (！ 标志[ I ] distances [ row ] [ I ] min ] { min=distances [ row ] [ I ]； minIndex=i； }if(minindex==22 ) { return -1； }返回mini
ndex;}int main(void) { double distances[21][21] = {{0}, {0}}; Graph(distances); double sum_all; flag[0] = true; for (int i = 0;i< 5;++i) { double sum = 0; double weight = 0; int minIndex = 0,finish = 0; while ((sum + distances[0][finish]) <= 50 || finish== 0) { minIndex = SeletMin(distances, minIndex,sum); if (minIndex == -1) { break; } if (sum + distances[finish][minIndex] + distances[0][minIndex]>50) { break; } if (weight + map[minIndex][2]>8) break; weight += map[minIndex][2]; cout << minIndex <<' '; flag[minIndex] = true; sum += distances[finish][minIndex]; finish = minIndex; } if(sum != 0) { sum = sum + distances[0][finish]; cout << endl; cout << sum<< endl; cout << weight << endl; } sum_all += sum; } cout << sum_all; return 0;} 2.变种贪心算法每次将最近距离的客户点分配给车。
#include <iostream>#include <algorithm>#include <stdlib.h>#include <cmath>using namespace std;double map[21][3] = {14.2,13.1,0,12.8,8.5,0.1,18.4,3.4,0.4,15.4,16.6,1.2,18.9,15.2,1.5,15.5,11.6,0.8,3.9,10.6,1.3,10.6,7.6,1.7,8.6,8.4,1.6,12.5,2.1,1.2,13.8,5.2,0.4,6.7,16.9,0.9,14.8,2.6,1.3,1.8,8.7,1.3,17.1,11,1.9,7.4,1,1.7,0.2,2.8,1.1,11.9,19.8,1.5,13.2,15.1,1.6,6.4,5.6,1.7,9.6,14.8,1.5};// Is visited?bool flag[21] = {false};double Dist(double x1, double y1, double x2, double y2) { return (double)pow((pow((x2 - x1), 2) + pow((y2 - y1), 2)), 0.5);}// Dist Matrixvoid Graph(double distances[21][21]) { for (int i = 0; i < 21; i++) { for (int j = i + 1; j < 21; j++) { distances[i][j] = Dist(map[i][0], map[i][1], map[j][0], map[j][1]); distances[j][i] = distances[i][j]; } distances[i][i] = 10000; }}// Index of Min Every Rowint SeletMin(double distances[21][21], int row, double sum) { double min = 10000; int minIndex = 22; for (int i = 0; i < 21; i++) { if (!flag[i] && distances[row][i] < min) { min = distances[row][i]; minIndex = i; } } if (minIndex == 22) { return -1; } return minIndex;}int main(void) { double distances[21][21] = {{0}, {0}}; Graph(distances); double sum_all = 0; flag[0] = true; double sum[5] = {0}; double weight[5] = {0}; int minIndex[5] = {0}; int finish[5] = {0}; int route[5][20] = {{0}, {0}}; int count = 20; while (count > 0) { //every vihicle one step for (int i = 0; i < 5; i++) { if ((sum[i] + distances[0][finish[i]]) <= 50 || finish[i] == 0) { minIndex[i] = SeletMin(distances, minIndex[i], sum[i]); } if (minIndex[i] == -1) { break; } if (sum[i] + distances[finish[i]][minIndex[i]] + distances[0][minIndex[i]]>50) { break; } if (weight[i] + map[minIndex[i]][2] > 8) { break; } flag[minIndex[i]] = true; count--; cout << "第" << i << "辆车选择" << minIndex[i] << endl; weight[i] += map[minIndex[i]][2]; sum[i] += distances[finish[i]][minIndex[i]]; finish[i] = minIndex[i]; } } for (int i = 0; i < 5; i++) { sum[i] += distances[0][finish[i]]; cout << "第" << i << "辆车路径为" << sum[i] << endl; sum_all += sum[i]; cout << "第" << i << "辆车重量为" << weight[i] << endl; } cout << sum_all << endl;// for(int i=0;i<21;i++)// {// for(int j=0;j<21;j++)// {// cout <<"["<< i << "][" << j << "]" << distances[i][j] <<" ";// }// cout<<endl;// } //while ((sum[i] + distances[0][finish[i]]) <= 50 || finish[i] == 0) { // minIndex[i] = SeletMin(distances, minIndex[i], sum[i]); // if (minIndex[i] == -1) { // break; // } // if (sum[i] + distances[finish[i]][minIndex[i]] + distances[0][minIndex[i]]>50) { // break; // } // if (weight[i] + map[minIndex[i]][2] > 8) { // break; // } // weight[i] += map[minIndex[i]][2]; // cout << minIndex[i] <<' '; // flag[minIndex[i]] = true; // sum[i] += distances[finish[i]][minIndex[i]]; // finish[i] = minIndex[i]; //} //if(sum[i] != 0) { // sum[i] = sum[i] + distances[0][finish[i]]; // cout << endl; // cout << sum[i] << endl; // cout << weight[i] << endl; //} //sum_all += sum[i]; return 0;}