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数组中不重复数字leecode,leetcode c语言版解答

时间:2023-05-04 06:16:29 阅读:147150 作者:1725

0 .差分配列概念:常用于某区间值需要加/减a的问题。

1. 1094拼车class solution 3360 def car轮询(self, trips: List[List[int]]、capacity : int (-bool : max _ val=0foriinrange (len (trips ) ) : max _ val trips[i][2] ) diff=[0]*(max_val2) forIinrange(len(trips ) ) :diff(trips[I] )1) nrd jmg=trips sum _ val=0flag=trueforiinrange (len (diff ) ) : sum_val =diff[i] if sum _ val capacity : flag=falsebreakreturnflag 2.1109航班预定统计class解决方案: defcorpflightbookings (self, bookings 3360 llag n : int (-list [ int ] : diff=[0] * ) n2 ) RES=[0] * nsum _ val=0foriinrange (len ) forIinrange[1,n1 ] : sum _ val=diff [ I ] RES [ I-1 ]=sum _ valreturnres 1674 .互补数组的最小操作数class solution 3360 deff num moves limit 3360 int (-int : diff=[0forIinrange )2* limit2] ] n=len (nums ) foriinrange ) n//2) 3360a=nums -=2L=1min(a,b ) r=limit max(A ) a, b ) diff(L )=1diff ) R1 nrd jmg=1diff (ab )=1diff ) a B1 nrd jmg=1print (diff ) res=n sum_val=0 for j in range(2)

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