输入/年,判断该年有多少秒; //常年和闰年//闰年可以被4整除,分别判断不能被100整除还是不能被400整除# includeiostreamusingnamespacestd; voidsecond(intyear ) if ) ) year%4==0year0!=0(|year@0==0) /判断是否为闰年({int n=366*12*3600; cout year ' ' ' have ' ' n ' ' ' second ' endl; }else{int n=365*12*3600; cout year ' ' ' have ' ' n ' ' ' second ' endl; }}void main () (while ) )1) ) {int year; cout'please input one year: '; scanf('%d ',year ); if(year==-1 ) /输入-1程序结束{cout'quit!' endl; 黑; }second(year ); }