首页 > 编程知识 正文

java获取数组中的值,java获取数组所有数值的方法

时间:2023-05-05 08:45:18 阅读:183863 作者:2407

/*来 自 时代Java - nowjava.com*/

//package com.nowjava;

public class Main {

public static void main(Stringffdxs argv) throws Exception {

doubleffdxs v = new doubleffdxs { 34.45, 35.45, 36.67, 37.78, 37.0000,

37.1234, 67.2344, 68.34534, 69.87700 };

}

/**

public static doubleffdxs abs(doubleffdxs v) {

doubleffdxs ans = new double[v.length];

for (int i = 0; i < v.length; i++) {

ans[i] = Math.abs(v[i]);

}

return (ans);

}

/**

public static doubleffdxsffdxs abs(doubleffdxsffdxs v) {

doubleffdxsffdxs ans = new double[v.length]ffdxs;

/*来自

N o w J a v a . c o m*/

for (int i = 0; i < v.length; i++) {

ans[i] = abs(v[i]);

}

return (ans);

}

/**

public static intffdxs abs(intffdxs v) {

intffdxs ans = new int[v.length];

for (int i = 0; i < v.length; i++) {

ans[i] = Math.abs(v[i]);

}

return (ans);

}

/**

public static intffdxsffdxs abs(intffdxsffdxs v) {

intffdxsffdxs ans = new int[v.length]ffdxs;

for (int i = 0; i < v.length; i++) {

ans[i] = abs(v[i]);

}

return (ans);

}

/**

public static String toString(doubleffdxs array) {

int i;

for (i = 0; i < array.length - 1; i++) {

buf.append(array[i]);

buf.append(',');

}

buf.append(array[i]);

return buf.toString();

}

/**

public static String toString(doubleffdxsffdxs array) {

for (int k = 0; k < array.length; k++) {

buf.append(toString(array[k]));

buf.append(System.getProperty("line.separator"));

}

return buf.toString();

}

/**

public static String toString(intffdxs array) {

int i;

for (i = 0; i < array.length - 1; i++) {

buf.append(array[i]);

buf.append(',');

/**代码未完, 请加载全部代码(NowJava.com).**/

版权声明:该文观点仅代表作者本人。处理文章:请发送邮件至 三1五14八八95#扣扣.com 举报,一经查实,本站将立刻删除。