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vlookup函数用法实例,sumproduct函数用法实例

时间:2023-05-06 06:45:39 阅读:206038 作者:1687

#include char *fgets(char *restrict buf, int n, FILE *restrict fp);返回值: 成功返回buf,若已到达文件结尾或出错则返回NULL;

实例:

1. 必须指定缓冲区的长度,函数一直读到下一个换行符;见实例 I

2. 最多读取n -1个字符,读入的字符被送入缓冲区,该缓冲区以null字符结尾;见实例 II

3. 如若该行(包含最后一个换行符)的字符数超过n - 1,fgets下次调用会继续改行;附件III

实例 I:缓冲区buf的长度一直读到下一个换行符

1.txt内容:

备注:1. 仅最后的a有换行符,第一行(和第二行)没有换行符.

xxdyx

*

0000420 a a a a n

0000425

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

源码&& 运行结果:

root@ubuntu:/opt/linux# cat 1.c 1.txt

#include #include int main()

{

FILE *stream;

char buf1[4096];

char buf2[1024];

stream = fopen("1.txt","r+");

if(stream == NULL)

{

return -1;

}

fgets(buf1,1024,stream);

printf("%sn",buf1);

return 0;

}

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

root@ubuntu:/opt/linux# gcc 1.c

root@ubuntu:/opt/linux# ./a.out

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

实例II:最多读取n-1个字符。

1.txt内容:

root@ubuntu:/opt/linux# od -c 1.txt

0000000 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5

0000020 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1

0000040 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7

0000060 8 9 n

0000063

1.txt内容:

root@ubuntu:/opt/linux# cat 1.txt

01234567890123456789012345678901234567890123456789

root@ubuntu:/opt/linux#

源码&& 运行结果:

root@ubuntu:/opt/linux# cat 1.c;gcc 1.c;./a.out

#include #include int main()

{

FILE *stream;

char buf1[4096];

char buf2[1024];

stream = fopen("1.txt","r+");

if(stream == NULL)

{

return -1;

}

fgets(buf1,11,stream);

printf("%sn",buf1);

return 0;

}

0123456789

root@ubuntu:/opt/linux#

实例III:

1.txt内容与结构:

0000000 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5

0000020 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1

0000040 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7

0000060 8 9 h e l l o w o r l d ! n n

0000100

root@ubuntu:/opt/linux# cat 1.txt

01234567890123456789012345678901234567890123456789hello world!

root@ubuntu:/opt/linux#

2.源码 && 运行结果:

root@ubuntu:/opt/linux# cat 1.c

#include #include int main()

{

FILE *stream;

char buf1[4096];

char buf2[1024];

stream = fopen("1.txt","r+");

if(stream == NULL)

{

return -1;

}

fgets(buf1,51,stream);

fgets(buf2, 1000,stream);

printf("tbuf1 is %sn",buf1);

printf("tbuf2 is %sn",buf2);

return 0;

}

root@ubuntu:/opt/linux# ./a.out

buf1 is 01234567890123456789012345678901234567890123456789

buf2 is hello world!

root@ubuntu:/opt/linux#

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