杭电ACM试题健康的眼神
【杭电ACM1000】
A + B Problem
Problem Description
Calculate A + B.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, output A + B in one line.
Sample Input
1 1
Sample Output
2
# include
int main()
{
int a, b;
while(scanf("%d%d", &a, &b)!=EOF)
printf("%dn", a+b);
return 0;
}
【杭电ACM1001】
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1 100
Sample Output
1 5050
# include
int main()
{
int n, i, sum = 0;
while(scanf("%d", &n)!=EOF)
{
for(i=1; i<=n; ++i)
sum = sum + i;
printf("%dnn", sum);
sum = 0;
}
return 0;
}
【杭电ACM1002】
A + B Problem II
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
Sample Input
2 1 2 112233445566778899 998877665544332211
Sample Output
Case 1: 1 + 2 = 3 Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110
#include
#include
int shu(char a)
{
return (a-'0');
}
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