def f(n):
#1.先把数字转换为字符串
n = str(n)
#2.计算字符串中每个数的平方
sum = 0
for item in n:
sum += int(item) ** 2
return sum
print(f(207))
#1.接收变量 k,a,b
s = input()
#2.存储整型k,a,b
li = []
for item in s.split():
li.append(int(item))
k,a,b = li
#3.进行判断是否满足条件
count = 0
for i in range(a,b+1):
if k*f(i) == i:
count += 1
print(count)