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python怎样计算时间,python如何获得某年某月的天数

时间:2023-05-04 02:24:35 阅读:215273 作者:3815

#!/usr/bin/env python

# -*- coding:utf-8 -*-

import datetime

import collections

def date_list_fun(starttime,endtime):

'''计算输入的起始日期和结束日期之间的所有日期'''

_u=datetime.timedelta(days=1)

startdate=datetime.datetime.strptime(starttime,'%Y%m%d')

enddate=datetime.datetime.strptime(endtime,'%Y%m%d')

n=0

date_list=[]

if startdate<=enddate:

# print startdate,enddate

while 1:

_time=startdate+n*_u

date_list.append(_time.strftime('%Y%m%d'))

n=n+1

if _time==enddate:

break

return date_list

def allweeks(year):

'''计算一年内所有周的具体日期,从1月1号开始,12.31号结束

'''

start_date=datetime.datetime.strptime(str(year)+'0101','%Y%m%d')

end_date=datetime.datetime.strptime(str(year)+'1231','%Y%m%d')

_u=datetime.timedelta(days=1)

n=0

week_date={}

while 1:

_time=start_date+n*_u

w=str(int(_time.strftime('%W'))+1)

week_date.setdefault(w,[]).append(_time.strftime('%Y%m%d'))

n=n+1

if _time==end_date:

break

week_date_start_end={}

for i in week_date:

week_date_start_end[i]=[week_date[i][0],week_date[i][-1]]

print week_date

print week_date_start_end

return week_date

def all_weeks(year):

'''计算一年内所有周的具体日期,每周都是7天,可能最后一周到 下年

week_date 输出如{1: ['20181231', '20190101', '20190102', '20190103', '20190104', '20190105', '20190106'],...}

计算一年内所有周的起始日期

week_date_start_end {1: ['20181231','20190106'],...}

'''

start_date=datetime.datetime.strptime(str(int(year)-1)+'1224','%Y%m%d')

end_date=datetime.datetime.strptime(str(int(year)+1)+'0107','%Y%m%d')

_u=datetime.timedelta(days=1)

n=0

week_date={}

while 1:

_time=start_date+n*_u

y,w=_time.isocalendar()[:2]

if y==year :

week_date.setdefault(w,[]).append(_time.strftime('%Y%m%d'))

n=n+1

if _time==end_date:

break

week_date_start_end={}

for i in week_date:

week_date_start_end[i]=[week_date[i][0],week_date[i][-1]]

print week_date

# print week_date_start_end

return week_date,week_date_start_end

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