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r的平方值,Python/R

时间:2023-05-04 21:57:27 阅读:219097 作者:4183

import numpy as np

from astropy.units import Ybarn

import math

def computeCorrelation(x, y):
xBar = np.mean(x)
ybar = np.mean(y)
SSR = 0
varX = 0
varY = 0
for i in range(0, len(x)): #多少实例
diffxxBar = x[i] - xBar
diffyyBar = y[i] - ybar
SSR += (diffxxBar * diffyyBar)
varX += diffxxBar ** 2 # 求平方然后累计起来
varY += diffyyBar ** 2 # 求平方然后累计起来

SST = math.sqrt(varX * varY)return SSR / SST

def polyfit(x, y, degree):

result = {} # 定义一个字典coeffs = np.polyfit(x, y, degree) # 直接求出b0 b1 b2 b3 ..的估计值result["polynomial"] = coeffs.tolist()p = np.poly1d(coeffs) # 返回预测值yhat = p(x) # 传入x 返回预测值ybar = np.sum(y) / len (y) # 求均值ssreg = np.sum((yhat -ybar)**2)sstot = np.sum((y - ybar)**2)result["determination"] = ssreg / sstotreturn result

testX = [1, 3, 8, 7, 9]
testY = [10, 12, 24, 21, 34]

print(“r:”, computeCorrelation(testX, testY))
print(“r**2:”, (computeCorrelation(testX, testY)**2))

print(“r**2”, polyfit(testX, testY, 1)[“determination”]) # degree=1 一次
print(polyfit(testX, testY, 1)[“polynomial”]) # 打印除斜率和截距

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