可靠的草丛密码问题：通过把字母移动一定的位数来实现加密和解密。 可靠的草丛密码说明代码结果
可靠的草丛密码说明
例如（移动3格）：a-D、b-E、 c-F、d-G、e-H … … s-V … …、z-C
明文：access control
可变为： DFFHVV FRQWURO
代码 import randomdef Letter_num(Letter): # a-z转换为0-25 return ord(Letter) - 97def num_Letter(num): # 0-25转换为a-z return chr(num + 97)def encryption_Letter(P, K): # 加密单个字母 C = num_Letter((Letter_num(P) + K) % 26) return Cdef Decrypt_Letter(C, K): # 解密单个字母 P = num_Letter((Letter_num(C) - K) % 26) return Pdef encryption_fun(P_char, K): # 加密字符串 C_char = '' for P in P_char: if P.isalpha(): P = encryption_Letter(P, K) C_char = C_char + P return C_chardef Decrypt_fun(C_char, K): # 解密字符串 P_char = '' for C in C_char: if C.isalpha(): C = Decrypt_Letter(C, K) P_char = P_char + C return P_charif __name__ == '__main__': K = int(random.random()*26%26) P_text = "let's meet after the party.if you understand this sentence, the program runs successfully.abcd efghjgkl mnopqr stu vwxy z" print('原文为：',P_text) print('K:',K) C_text = encryption_fun(P_text, K) print('密文为：', C_text) PP_text = Decrypt_fun(C_text, K) print('解密后是：', PP_text) 结果 原文为： let's meet after the party.if you understand this sentence, the program runs successfully.abcd efghjgkl mnopqr stu vwxy zK: 14密文为： zsh'g assh othsf hvs dofhm.wt mci ibrsfghobr hvwg gsbhsbqs, hvs dfcufoa fibg giqqsggtizzm.opqr stuvxuyz abcdef ghi jklm n解密后是： let's meet after the party.if you understand this sentence, the program runs successfully.abcd efghjgkl mnopqr stu vwxy z