1.三个售票窗口同时出售20张票
public class Demo1{ public static void main(String[] args) { TicketOffice ticketOffice = new TicketOffice(new Object(), 20); new Thread(ticketOffice, "窗口1").start(); new Thread(ticketOffice, "窗口2").start(); new Thread(ticketOffice, "窗口3").start(); }}class TicketOffice implements Runnable{ private Object object; private int ticketNum; public TicketOffice(java.lang.Object object, int ticketNum) { this.object = object; this.ticketNum = ticketNum; } @Override public void run() { while (ticketNum > 0) { synchronized (object) { if (ticketNum <= 0) { System.out.println(Thread.currentThread().getName() + "没有票了"); } else { System.out.println(Thread.currentThread().getName() + "卖出了一张票，剩余" + --ticketNum + "张票"); try { Thread.sleep(1000L); } catch (InterruptedException e) { e.printStackTrace(); } } } } }}2.创建两个线程，其中一个输出1-52，另外一个输出A-Z。输出格式要求：12A 34B 56C 78D ...
public class Demo2{ public static void main(String[] args) { Object object = new Object(); new Thread(new Number(object)).start(); new Thread(new Character(object)).start(); }}class Number implements Runnable{ private Object object; public Number(Object object) { this.object = object; } @Override public void run() { synchronized (object) { for (int i = 1; i < 53; i++) { if (i > 1 && i % 2 == 1) { System.out.print(" "); } System.out.print(i); if (i % 2 == 0) { object.notifyAll(); try { object.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } } } }}class Character implements Runnable{ private Object object; public Character(Object object) { this.object = object; } @Override public void run() { synchronized (object) { for (char i = 'A'; i <= 'Z'; i++) { System.out.print(i); object.notifyAll(); if (i < 'Z') { try { object.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } } } }}3.
启动3个线程打印递增的数字, 线程1先打印1,2,3,4,5, 然后是线程2打印6,7,8,9,10, 然后是线程3打印11,12,13,14,15. 接着再由线程1打印16,17,18,19,20….以此类推, 直到打印到75. 程序的输出结果应该为:
线程1: 1
线程1: 2
线程1: 3
线程1: 4
线程1: 5
线程2: 6
线程2: 7
线程2: 8
线程2: 9
线程2: 10
…
线程3: 71
线程3: 72
线程3: 73
线程3: 74
线程3: 75