STM32 在keil下进行strtol函数的功能测试,支付功能怎么进行测试

STM32 在keil下进行strtol函数的功能测试

源码：

void test_str2num_strtol(void){ int a; printf("rnrn0x1234 = %d,",strtol("0x1234",NULL,0)); printf("rn1234 = %d,",strtol("1234",NULL,0)); printf("rnHex:1234 = %d,",strtol("1234",NULL,16)); printf("rn0 = %d,",strtol("0",NULL,0)); printf("rn01234 = %d,",strtol("01234",NULL,0)); printf("rn0.1234 = %d,",strtol("0.1234",NULL,0)); printf("rn-1234 = %d,",strtol("-1234",NULL,0)); printf("rn1234ab = %d,",strtol("1234ab",NULL,0)); printf("rn0b1011 = %d,",strtol("0b1011",NULL,0)); printf("rnbhdmg:0b1011 = %d,",strtol("0b1011",NULL,2)); printf("rnbhdmg:1011 = %d,",strtol("1011",NULL,2)); printf("rn0xB = %d,",strtol("0xB",NULL,0)); printf("rnabc1234 = %d,rn",strtol("abc1234",NULL,0));}

输出：

0x1234 = 4660,1234 = 1234,Hex:1234 = 4660,0 = 0,01234 = 668,0.1234 = 0,-1234 = -1234,1234ab = 1234,0b1011 = 0,bhdmg:0b1011 = 0,bhdmg:1011 = 11,0xB = 11,abc1234 = 0,

可以看出，这个函数:

如果最后一个参数设置为0的话，会默认把字符串当作10进制进行转换;

如果0x开头，则以16进制转换;

如果以0开头，则以8进制进行转换;

如果最后一个参数为 2 的话,那么就会以二进制转换;

如果是16则以16进制进行转换。

出错，就返回0.

如果以其他字符开头，则以出错返回0.

如果后面有不可识别的字符，则只转换前面的数字。