满意答案
qraalapke
2017.04.12
采纳率:52% 等级:8
已帮助:162人
#include
#include
void convert(char *input, char *output)
{
int len1 = strlen(input); //输入二进制数位数
int pos = len1 / 4 + 1; //输出十六进制数的位数
if (len1 % 4 == 0)
{
pos = pos - 1;
}
int j = 0;
while (len1>0)
{
char sum = 0;
for (int i=0; i<4 && len1>0; i++, len1--) //从最后起每4位算一次值
{
sum = sum + (input[len1-1]-'0')*pow(2, i);
}
// 转换成16进制数表示
sum = sum + '0';
if ('9'
{
sum = sum + 7;
}
else if (sum > '9' + 6)
{
printf("您输入的不是正确的2进制数!n");
exit(0);
}
//十六进制数放到output数组相应位置
output[--pos] = sum;
}
}
int main()
{
int groupNum = 0;
char total[1024] = {0};
scanf("%d", &groupNum);
for (int i=1; i<=groupNum; i++)
{
char input[1024] = {0};
char output[256] = {0};
fflush(stdin); //记得清楚输入缓冲区,否则每次回车会影响
gets(input);
convert(input, output);
char format[32] = {0};
sprintf(format, "nCase %d: ", i);
strcat(total, format);
strcat(total, output);
}
printf("%sn", total);
}
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