列表去重 python,python对列表进行去重

python列表去重的九种实现方式 实现方式非常多，但都是从几种方法延伸而来，我总结的基本方法有5种，利用复杂的流程控制，if判断进行不同的实现方式，目前延伸出9种实现方式如下，可自行测试，后面发现新的实现方式会持续更新 # 方法一# 利用集合的元素唯一性，对列表进行去重def three_question(): li = [11, 22, 33, 22, 22, 44, 55, 77, 88, 99, 11] se = set(li) print('列表中不重复元素个数：',len(se))# three_question()# 方法二# 定义一个空列表，用for循环遍历要去重的列表，判断不存在与新定义的空列表的元素就添加实现去#重def three_question02(): li = [11, 22, 33, 22, 22, 44, 55, 77, 88, 99, 11] li2 = [] for item in li: if item not in li2: li2.append(item) else: continue print('列表中不重复元素个数：',len(li2))# three_question02()# 方法三# 利用嵌套for循环，比对出重复元素进行删除操作，实现列表去重def three_question03(): li = [11, 22, 33, 22, 22, 44, 55, 77, 88, 99, 11] num=0 for item in li[0:]: num+=1 for id in li[num:]: if id == item: li.remove(id) else: continue print(li) print('列表中不重复元素个数：', len(li))# three_question03()# 第四种 将值转化为字典的键值,利用键值的唯一性def three_question04(): print("第三种 将值转化为字典的键值,利用键值的唯一性") li=[11, 22, 33, 22, 22, 44, 55, 77, 88, 99, 11] dict1={} for i in li: dict1[i]=i number=len(dict1) print("列表中不重复的元素个数为：{}".format(number))# three_question04()# 方法五：def three_question05(): li = [11, 22, 33, 22, 22, 44, 55, 77, 88, 99, 11] li3 =[] s=set() for i in li: if li.count(i) == 1: if i not in li3: li3.append(i) elif li.count(i)>1: s.add(i) for se in s: li3.append(se) print('不重复元素个数',len(li3))# three_question05()# 方法六：def three_question06(): li = [11, 22, 33, 22, 22, 44, 55, 77, 88, 99, 11] li3 =[] s={} for i in li: if li.count(i) == 1: if i not in li3: li3.append(i) elif li.count(i)>1: s[i]=i for se in s.values(): li3.append(se) print('不重复元素个数',len(li3))# three_question06()#方法七:(利用字典健值去重)字典函数去重def three_question07(): li=[11, 22, 33, 22, 22, 44, 55, 77, 88, 99, 11] d = {} d = d.fromkeys(li) li2 = list(d.keys()) print(li2) print('不重复元素个数', len(li2))# three_question07()# 方法八：def three_question08(): li=[11, 22, 33, 22, 22, 44, 55, 77, 88, 99, 11] li3=[] index=0 while index < len(li): if li[index] not in li3: li3.append(li[index]) index += 1 if index >= len(li): break print('不重复元素个数',len(li3))# three_question08()# 方法九：def three_question09(): li=[11, 22, 33, 22, 22, 44, 55, 77, 88, 99, 11] formatList = list(set(li)) formatList.sort(key=li.index) print('不重复元素个数',len(formatList))three_question09()