Possible Duplicate:
07000
当我运行我的php页面时,我收到此错误并且不知道什么是错的,有人可以帮忙吗？如果有人需要更多信息,我会发布整个代码.
Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in
H:Program FilesEasyPHP 2.0b1wwwtestinfo.php on line 16
$user_name = "root";
$password = "";
$database = "addressbook";
$server = "127.0.0.1";
$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);
if ($db_found) {
$SQL = "SELECT * FROM tb_address_book";
$result = mysql_query($SQL);
while ($db_field = mysql_fetch_assoc($result)) {
print $db_field['ID'] . "
";
print $db_field['First_Name'] . "
";
print $db_field['Surname'] . "
";
print $db_field['Address'] . "
";
}
mysql_close($db_handle);
}
else {
print "Database NOT Found ";
mysql_close($db_handle);
}
?>