计算方法及每一步详解源自：https://www.bilibili.com/video/BV1R7411y7kw
python实现
import mathdef BvToAv(Bv): # 1.去除Bv号前的"Bv"字符 BvNo1 = Bv[2:] keys = { '1': '13', '2': '12', '3': '46', '4': '31', '5': '43', '6': '18', '7': '40', '8': '28', '9': '5', 'A': '54', 'B': '20', 'C': '15', 'D': '8', 'E': '39', 'F': '57', 'G': '45', 'H': '36', 'J': '38', 'K': '51', 'L': '42', 'M': '49', 'N': '52', 'P': '53', 'Q': '7', 'R': '4', 'S': '9', 'T': '50', 'U': '10', 'V': '44', 'W': '34', 'X': '6', 'Y': '25', 'Z': '1', 'a': '26', 'b': '29', 'c': '56', 'd': '3', 'e': '24', 'f': '0', 'g': '47', 'h': '27', 'i': '22', 'j': '41', 'k': '16', 'm': '11', 'n': '37', 'o': '2', 'p': '35', 'q': '21', 'r': '17', 's': '33', 't': '30', 'u': '48', 'v': '23', 'w': '55', 'x': '32', 'y': '14', 'z': '19' } # 2. 将key对应的value存入一个列表 BvNo2 = [] for index, ch in enumerate(BvNo1): BvNo2.append(int(str(keys[ch]))) # 3. 对列表中不同位置的数进行*58的x次方的操作 BvNo2[0] = int(BvNo2[0] * math.pow(58, 6)) BvNo2[1] = int(BvNo2[1] * math.pow(58, 2)) BvNo2[2] = int(BvNo2[2] * math.pow(58, 4)) BvNo2[3] = int(BvNo2[3] * math.pow(58, 8)) BvNo2[4] = int(BvNo2[4] * math.pow(58, 5)) BvNo2[5] = int(BvNo2[5] * math.pow(58, 9)) BvNo2[6] = int(BvNo2[6] * math.pow(58, 3)) BvNo2[7] = int(BvNo2[7] * math.pow(58, 7)) BvNo2[8] = int(BvNo2[8] * math.pow(58, 1)) BvNo2[9] = int(BvNo2[9] * math.pow(58, 0)) # 4.求出这10个数的合 sum = 0 for i in BvNo2: sum += i # 5. 将和减去100618342136696320 sum -= 100618342136696320 # 6. 将sum 与177451812进行异或 temp = 177451812 return sum ^ tempif __name__ == '__main__': Bv = input("请输入Bv号:") print(Bv + "的Av号为:av" + str(BvToAv(Bv))) print("链接地址为：http://www.bilibili.com/video/av" + str(BvToAv(Bv)))运行结果：