首页 > 编程知识 正文

Python 程序:寻找元组中最大项

时间:2023-11-25 09:12:53 阅读:308948 作者:VZBO

编写一个 Python 程序来查找元组中最大或最大的项。这里,我们使用 Tuple max 函数返回最大的 Tuple 项。

# Tuple Max Item

mxTuple = (3, 78, 67, 34, 88, 11, 23, 19)
print("Tuple Items = ", mxTuple)

print("Largest Item in mxTuple Tuple = ", max(mxTuple))

寻找元组中最大项目的 Python 程序。

我们使用元组排序函数(sorted(mxTuple))以升序对元组进行排序。接下来,我们打印最后一个索引位置项,它是最大的。

# Tuple Max Item

mxTuple = (2, 14, 11, 19, 25, 17, 33, 22, 30) 
print("Tuple Items = ", mxTuple)

mxTuple = sorted(mxTuple)
print("Largest Item in mxTuple Tuple = ", mxTuple[len(mxTuple) - 1])
Tuple Items =  (2, 14, 11, 19, 25, 17, 33, 22, 30)
Largest Item in mxTuple Tuple =  33

在这个 Python 示例中,我们将 Tuple 第一个值指定为最大值(Tuple maximum = mxTuple[0]),for 循环范围从 1 开始,遍历到 mxTuple 长度。if 条件(if(最大值< mxTuple[I])) examines whether the current 元组项大于最大值。如果为真,则将该元组值赋给最大值,并将索引值赋给最大值变量。

# Tuple Max Item

mxTuple = (25, 17, 19, 33, 55, 22, 40, 30, 50, 29) 
print("Tuple Items = ", mxTuple)

tupLargest = mxTuple[0]
for i in range(1, len(mxTuple)):
    if(tupLargest < mxTuple[i]):
        tupLargest = mxTuple[i]
        tupLargestPos = i

print("Largest Item in mxTuple Tuple     = ", tupLargest)
print("Largest Tuple Item index Position = ", tupLargestPos)
Tuple Items =  (25, 17, 19, 33, 55, 22, 40, 30, 50, 29)
Largest Item in mxTuple Tuple     =  55
Largest Tuple Item index Position =  4

使用函数打印最大元组数的 Python 程序。

# Tuple Max Item

def tupleLargest(mxTuple):
    tupLargest = mxTuple[0]
    for i in mxTuple:
        if(tupLargest < i):
            tupLargest = i
    return tupLargest

mxTuple = (19, 25, 77, 56, 89, 45, 55, 12) 
print("Tuple Items = ", mxTuple)

lar = tupleLargest(mxTuple)
print("Largest Item in mxTuple Tuple = ", lar)
Tuple Items =  (19, 25, 77, 56, 89, 45, 55, 12)
Largest Item in mxTuple Tuple =  89

版权声明:该文观点仅代表作者本人。处理文章:请发送邮件至 三1五14八八95#扣扣.com 举报,一经查实,本站将立刻删除。