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php怎么链接sqlserver数据库进行增删改查
php有专门的sql server操作函数，举个简单的例子，是查询的
$serverName = "localhost"; //数据库服务器地址
$uid = "root"; //数据库用户名
$pwd = "123456"; //数据库密码
$connectionInfo = array("UID"=$uid, "PWD"=$pwd, "Database"='databasename');
$conn = sqlsrv_connect( $serverName, $connectionInfo);
if( $conn == false){
echo "连接数据库失败！";
die( print_r( sqlsrv_errors(), true));
}
$sql = "select * from user";
$query = sqlsrv_query( $conn, $sql , array(), array( "Scrollable" = SQLSRV_CURSOR_KEYSET ));
$num_rows = sqlsrv_num_rows($query);
if($num_rows 0){
while ($row = sqlsrv_fetch_array($query)){
echo $row['aaaa'];
}
}
其它的操作也同理，举一反三
求php增删改查代码。
class sqlHelper{
public $conn;
public $dbname="数据库名称";
public $username="数据库用户名";
public $password="数据库密码";
public $host="localhost";
//连接数据库
public function __construct(){
$this-conn=mysql_connect($this-host,$this-username,$this-password);
if(!$this-conn){
die("连接失败".mysql_error());
}
mysql_select_db($this-dbname,$this-conn);
}
//执行查询语句
public function execute_dql($sql){
$res=mysql_query($sql,$this-conn);
return $res;
}
//执行增填改语句
public function execute_dml($sql){
$b=mysql_query($sql,$this-conn);
if(!$b){
return 3;
}else{
if(mysql_affected_rows($this-conn)){
return 1;//表示OK
}else{
return 2;//表示没有行收到影响
}
}
}
}
如何用PHP代码实现MySQL数据库的增删改查
?php
$con = mysql_connect("localhost:3306","root","");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("test", $con);
$result = mysql_query("SELECT * FROM user");
echo "table border='1'
tr
thUsername/th
thPassword/th
/tr";
while($row = mysql_fetch_array($result)) {
echo "tr";
echo "td" . $row['username'] . "/td";
echo "td" . $row['password'] . "/td";
echo "/tr";
}
echo "/table";
mysql_close($con);
?
从服务器中获取用户所有信息（SQL SELECT语句）并以表格形式出现
?php
$con = mysql_connect("localhost","root","");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("test", $con);
mysql_query("DELETE FROM user WHERE username = '$_POST[username]'");
mysql_close($con);
?
删除该用户所有信息delete.php
?php
$con = mysql_connect("localhost:3306","root","");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("test", $con);
$sql = "INSERT INTO user (username,password)
VALUES
('$_POST[username]','$_POST[password]')";
if (!mysql_query($sql,$con)) {
die('Error: ' . mysql_error());
}
echo "1 record added";
mysql_close($con);
?
注册一个新用户insert.php
?php
$con = mysql_connect("localhost","root","");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("test", $con);
mysql_query("UPDATE user SET password = '$_POST[password]' WHERE username = '$_POST[username]'");
mysql_close($con);
?
修改一个用户密码update.php
html
head
titleFORM/title
/head
body
br /
h1Insert:/h1
form action="insert.php" method="post"
username:input type="name" name="username"/
br /
password:input type="password" name="password"/
input type="submit" value="submit"/
/form
br /hr /br /
h1Delete/h1
form action="delete.php" method="post"
username:input type="name" name="username" /
br /
Are you sure?input type="submit" value="sure" /
/form
br /hr /br /
h1Update/h1
form action="update.php" method="post"
username:input type="name" name="username"/
br /
You want to change your password into:input type="password" name="password"/
input type="submit" value="submit"/
/form
br /hr /br /
/body
/html
以上三个功能的提交源Operate.html
PHP 增删改查 急！！！！！！！
回答的有点晚。刚看到。你这种情况输出“修改失败”是很正常的
$result=$user-update($_POST);
if($user-update($_POST)){
你使用了两次更新。
第一次更新之后数据已经改变。再进行一次更新update返回结果是0（修改的行数）。
所以一直输出'修改失败'
建议修改
$result=$user-update($_POST);
if($result !== false){ // 此处未修改任何数据返回0的情况算为修改成功。