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java怎么将2个数组的数据合并？
concat()方法是对字符串的操作，不是对整数或数组。
concat（）用法：
String a="abc";
String b="edf";
String c=a.concat(b);
c的值为“abcdef"
数组可以用for循环合并:
public static void main(String[] args){
int a[]={1,7,9,11,13,15,17,19};
int b[]={2,4,6,8,10};
int aL=a.length;
int bL=b.length;
int lenght=aL+bL;
int[] c=new int[lenght];
for(int i=0;ilenght;i++){
if(iaL){//
c[i]=a[i];
}
else{
c[i]=b[i-aL];
}
}
for(int i=0;ic.length;i++){
System.out.print(c[i]+" ");
}
}
Java中如何把两个数组合并为一个
import java.util.Arrays;
//Java中如何把两个数组合并为一个
public class gog {
public static void main(String[] args) {
String [] str1 = {"J","a","v","a","中"};
String [] str2 = {"如","何","把","两","个","数","组","合","并","为","一","个"};
int strLen1=str1.length;//保存第一个数组长度
int strLen2=str2.length;//保存第二个数组长度
str1= Arrays.copyOf(str1,strLen1+ strLen2);//扩容
System.arraycopy(str2, 0, str1, strLen1,strLen2 );//将第二个数组与第一个数组合并
System.out.println(Arrays.toString(str1));//输出数组
}
}
Java如何合并两个数组
java数组合并问题
三种字符数组合并的方法
public static String[] getOneArray() {
String[] a = { "0", "1", "2" };
String[] b = { "0", "1", "2" };
String[] c = new String[a.length + b.length];
for (int j = 0; j a.length; ++j) {
c[j] = a[j];
}
for (int j = 0; j b.length; ++j) {
c[a.length + j] = b[j];
}
return c;
}
public static Object[] getTwoArray() {
String[] a = { "0", "1", "2" };
String[] b = { "0", "1", "2" };
List aL = Arrays.asList(a);
List bL = Arrays.asList(b);
List resultList = new ArrayList();
resultList.addAll(aL);
resultList.addAll(bL);
Object[] result = resultList.toArray();
return result;
}
public static String[] getThreeArray() {
String[] a = { "0", "1", "2", "3" };
String[] b = { "4", "5", "6", "7", "8" };
String[] c = new String[a.length + b.length];
System.arraycopy(a, 0, c, 0, a.length);
System.arraycopy(b, 0, c, a.length, b.length);
return c;
}
1.两个字符数组合并的问题
public String[] getMergeArray(String[] al,String[] bl) {
String[] a = al;
String[] b = bl;
String[] c = new String[a.length + b.length];
System.arraycopy(a, 0, c, 0, a.length);
System.arraycopy(b, 0, c, a.length, b.length);
return c;
}
2.字符数组和整形数组合并问题
public int[] getIntArray(int[] al,String[] bl) {
int[] a = al;
String[] b = bl;
int[] ia=new int[b.length];
for(int i=0;ib.length;i++){
ia[i]=Integer.parseInt(b[i]);
}
int[] c = new int[a.length + ia.length];
System.arraycopy(a, 0, c, 0, a.length);
System.arraycopy(ia, 0, c, a.length, ia.length);
return c;
}
JAVA数组合并请高手指教
a3[a3.length-j]=a2[a2.length-j];} //将a2[i]放入a3[i]中
改为a3[a3.length-j-1]=a2[a2.length-j-1];}
否则数组会溢出
至于排序，你是不是想用插入排序啊，你写的不太对头，我把排序重写一遍
public class C {
public static void main(String[] args) {
int[] a1 = { 20, 40, 50, 70, 90 };
int[] a2 = { 10, 30, 40, 60, 80 };
int[] a3 = new int[a1.length + a2.length];
for (int i = 0; i a1.length; i++) {
a3[i] = a1[i];
}
for (int j = 0; j a2.length; j++) {
a3[a3.length - j - 1] = a2[a2.length - j - 1];
}
for (int i : a3) {
System.out.println(i);//排序前输出a3
}
for (int i = 1; i a3.length; i++) {
if (a3[i - 1] a3[i]) {
int tmp = a3[i];
int j = i - 1;
do {
a3[j + 1] = a3[j];
j--;
} while (j = 0 tmp a3[j]);//当j=0并且 当前值大于数据中j位置的值时移动
a3[j + 1] = tmp; //插入排序值
}
}
System.out.println（"after sort:"）
for (int i : a3) {
System.out.println(i);//排序后输出a3
}
System.out.println();
}
}
java中怎么合并两个数组 简单明了的
int[] arr1 = {1,2,3,4,11};
int[] arr2 = {6,7,8,9,10};
int newLength = arr1.length + arr2.length;
int[] arr_target = new int[newLength];
//参数：源数组，源数组起始位置，目标数组，目标数组起始位置，复制长度
System.arraycopy(arr1, 0, arr_target, 0, arr1.length);
System.arraycopy(arr2, 0, arr_target, arr1.length, arr2.length);
//输出合并后数组
for (int i : arr_target) {
System.out.println(i);
}
//排序
Arrays.sort(arr_target);
//输出排序数组
for (int i : arr_target) {
System.out.println(i);
}
//逆序
int[] arr_reverse = new int[newLength];
int flag = 0;
for (int i : arr_target) {
arr_reverse[newLength - flag - 1] = i;
flag++;
}
//输出逆序数组
for (int i : arr_reverse) {
System.out.println(i);
}
数组合并不一定非得遍历
具体的输出题主自己再修改吧