c语言实现复数的加减乘除,c语言计算复数的加减乘除

这个程序我是在VC++6.0上运行的

#include

using namespace std;

class complex

{

public:

complex(){real=0;image=0;}

complex(double a,double b):real(a),image(b){}

complex operator+(complex &);

complex operator-(complex &);

complex operator*(complex &);

complex operator/(complex &);

void display()

{

cout<

if (image>0)

cout<

cout<

}

private:

double real;

double image;

};

complex complex::operator+(complex &temp)

{

return complex(real+temp.real,image+temp.image);

}

complex complex::operator-(complex &temp)

{

return complex(real-temp.real,image-temp.image);

}

complex complex::operator*(complex &temp)

{

return complex(real*temp.real-image*temp.image,real*temp.image+image*temp.real);

}

complex complex::operator/(complex &temp)

{

complex c;

c.real=(real*temp.real+image*temp.image)/(temp.real*temp.real+temp.image*temp.image);

c.image=(real*temp.image*(-1)+image*temp.real)/(temp.real*temp.real+temp.image*temp.image);

return c;

}

int main()

{

complex c1(15,3),c2(5,1),c3;

c3=c1+c2;

c3.display();

c3=c1-c2;

c3.display();

c3=c1*c2;

c3.display();

c3=c1/c2;

c3.display();

return 0;

}

运行结果为20+4i

10+2i

72+30i

30i

我对最后一个结果不明白,我认为是3