关于求解中位数，我们知道在Python中直接有中位数处理函数（mean)，比如在Python中求解一个中位数，代码很简单。
Python计算中位数
import numpy as npnums = [1.1,2.2,3.3,4.4,5.5,6.6]均值
np.mean(nums)中位数
np.median(nums)在hive中没有直接提供相关的mean函数，但官方提供了两个UDAF，percentile和percentile_approx。
我们看下官方是怎么说的
DOUBLEpercentile(BIGINT col, p)Returns the exact pthpercentile of a
column in the group (does not work with floating point types). p must
be between 0 and 1. NOTE: A true percentile can only be computed for
integer values. Use PERCENTILE_APPROX if your input is non-integral.
arraypercentile(BIGINT col, array(p1[, p2]…))Returns the exact
percentiles p1, p2, … of a column in the group (does not work with
floating point types). pimust be between 0 and 1. NOTE: A true
percentile can only be computed for integer values. Use
PERCENTILE_APPROX if your input is non-integral.
DOUBLEpercentile_approx(DOUBLE col, p [, B])Returns an approximate
pthpercentile of a numeric column (including floating point types) in
the group. The B parameter controls approximation accuracy at the
cost of memory. Higher values yield better approximations, and the
default is 10,000. When the number of distinct values in col is
smaller than B, this gives an exact percentile value.
arraypercentile_approx(DOUBLE col, array(p1[, p2]…) [, B])Same as
above, but accepts and returns an array of percentile values instead
of a single one.
请注意，官方文档上说了一句话：NOTE: A true percentile can only be computed for integer values. UsePERCENTILE_APPROX if your input is non-integral.
也就是说，真正的中位数只能用percentile来计算，输入需要为整数类型，使用percentile_approx（输入为浮点型）计算得到的并不是真正的中位数，也就是所说的近似中位数，经过大量数据验证，有时候这个近似中位数和真正的中位数差别还是很大的。
如何对有小数的数据求取中位数呢？
可以把小数转换为整数，然后再求取中位数（如先✖️乘10000）
sparksql中也是如此求取中位数的，赶快去试一试吧！