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randles sevcik方程中文名,codeforces中文官网

时间:2023-05-06 15:57:27 阅读:166836 作者:4745

主题链接:单击主题b.restoringpaintingtimelimitpertest1secondmemorylimitpertest 256 megabytesinputstandardinputoutputstandardoutstandardoute font-size:1em; 行高度:1.4 em; margin-top:0px! 导入; 边距- bottom :1 em! important ' dpdmlaworksasawatchmaninthegallery.unfortunately,oneofthemostexpensivepaintingswasstolenwhilehewasonduty.he

3个the painting is a square,eachcellcontainsasingleintegerfrom1ton,andifferentcellsmaycontaineitherdifferentorequalintegegers thetopleftsquare 22.fourelementsa,b, canddareknownandarelocatedasshownonthepicturebelow.helpgldpyfindoutthenumberofdistinctsquaresthesatisfyalltheconditionsabove that this number may be equal to0,meaninggldpyrememberssomethingwrong。

twosquaresareconsideredtobedifferent,ifthereexistsacellthatcontainstwodifferentegersindifferentsquares。

inputthefirstlineoftheinputcontainsfiveintegersn,a,b,candd (1n100,000,1a,b,c,dn )-maximumposposssibibibibibibid

outputprintoneinteger-thenumberofdistinctvalidsquares。

examples input 2112 output2input 3123 output6notebelowareallthepossiblepaintingsforthefirstsample。

In the second sample,onlypaintingsdisplayedbelowsatisfyalltherules。

果然是读问题的问题。 如下。 #include cstdioint main () ({__int64 ans=0; int n; int a、b、c、d; int e,f,I,h; scanf (% d % d % d % d % d % d % d )、n、a、b、c、d ); for(e=1; e=n; e () {f=e b - c; h=e a - d; i=f a - d; if(f=1f=nh=1h=nI=1I=n ) ans; }ans *=n; printf(%I64d(n ),ans ); 返回0; }

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