python求定积分,左黎曼和

Talk is cheap. Show me the code. a是积分下限，b是积分上限 f是被积函数 public class RiemannSum {public static void main(String奋斗的大叔 args) {final int times = 100000000;double a, b;double sum = 0;a = 1;b = 3;double delta = (b - a) / times;for (int i = 1; i <= times; i++) {sum += delta * fSin(a + i * delta);}System.out.println(sum);}public static double f(double a) {return Math.pow(a, 4);}public static double fSin(double a) {return Math.sin(a);}}

Python版本：

import mathdef f(a): return math.pow(a,2)times = 10000000riemannSum = 0;a = 1;b = 3;delta = (b - a) / timesfor i in range(1,times+1): riemannSum += delta * math.sin(a + i * delta)print(riemannSum)