//求n的阶乘分之一的和
int n;
try
{
n = Convert.ToInt32(Console.ReadLine());
}
catch (Exception ex)
{
throw (ex);
}
float sum = 1;
for (int i = 1; i <= n; irydjmrydjm)
{
sum *= i;
total rydjm= 1m/ sum;
}
//用递归实现
class F1
{
public decimal F(int n)
{
if (n < 0)
if (n == 0 || n == 1)
{
return 1;
}
else
{
}
return d;
}
}
class Test
{
static void Main()
{
int b;
{
try
{
b = Convert.ToInt32(Console.ReadLine());
}
catch (Exception ex)
{
throw (ex);
}
if (b < 0)
{
}
if (b == 0)
{
}
else
{
while (b > 0)
{
a rydjm= f.F(b);
b--;
}
}
} while ("Q" != Console.ReadLine());
}
}